(-4x^2)+7x+11=0

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Solution for (-4x^2)+7x+11=0 equation:



(-4x^2)+7x+11=0
We get rid of parentheses
-4x^2+7x+11=0
a = -4; b = 7; c = +11;
Δ = b2-4ac
Δ = 72-4·(-4)·11
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-15}{2*-4}=\frac{-22}{-8} =2+3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+15}{2*-4}=\frac{8}{-8} =-1 $

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